Question

an object is dropped from rest. if it falls distance x during first second and additional distance y on next 2 seconds . then ratio of x/y is ​

Answer 1

The answer of your question is approximate equals to

=》》》1:8

Answer 2

$\huge{\mathcal{BONJOUR \: !!}}$

Answer....

$by \: second \: eq. \: of \: motion \\ \\ s \: = \: ut \: + \frac{1}{2} a {t}^{2} \\ \\ here \: u \: = 0 \\ \\ so \\ \\ s \: = \frac{1}{2} a {t}^{2} \\ \\ s_1 = \frac{1}{2} \times 9.8 \times {1}^{2} \\ \\ s_1 = 4.9 \: m \: = x \\ \\ s_3 = \frac{1}{2} \times 9.8 \times {3}^{2} \\ \\ s_3 = 44.1 \: m \\ \\ y \: = 44.1 - 4.9 = 39.2 \: m \\ \\ so \: the \: ratio \: will \: be \: \\ \\ \frac{x}{y} = \frac{4.9}{39.2} = \frac{1}{8}$

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