Question

. An object is dropped from rest. If it falls distance
x during first second and additional distance y in
next two seconds. Then ratio of x/y is​

Answer 1

Answer:

Then ratio of x/y is​ 1:8

Explanation:

An object is dropped from rest.

Now if we assume,

p= bt + (1/2) at^2

Where b is the velocity, t is the time a is the gravitational force.

Then,

If it falls distance

x during first second

Then b= 0

t1 = 1 s

a = 9.8 m/s^2

p1 = (1/2)x9.8

p1 = 4.9 m

additional distance y in

next two seconds

for t=3 s ,

p2 = 0 + ( 1/2 ) x 9.8 x 3^2 = 44.1 m

y = 44.1 - 4.9 = 39.2 m

Then ratio of x/y is​

x:y

=4.9:39.2

= 1:8 .

Answer 2

Answer:

Then ratio of x/y is​ 1:8

Explanation:

An object is dropped from rest.

Now if we assume,

p= bt + (1/2) at^2

Where b is the velocity, t is the time a is the gravitational force.

Then,

If it falls distance

x during first second  

Then b= 0

t1 = 1 s

a = 9.8 m/s^2  

p1 = (1/2)x9.8  

p1 = 4.9 m

additional distance y in

next two seconds

for t=3 s ,

p2 = 0 + ( 1/2 ) x 9.8 x 3^2 = 44.1 m

y = 44.1 - 4.9 = 39.2 m

Then ratio of x/y is​

x:y  

=4.9:39.2

= 1:8 .