Question

an object is dropped from the height of 19.6 M draw the displacement time graph for the time when object reach the ground also find velocity of the object when it touches the ground​.... On chapter Motion & It's Description​

Answer 1

Answer:

acceleration due to gravity (a or g ) = 9.8 ms^-1

Height (s) = 19.6 m

Initial velocity (u) = 0 ms^-1

S= ut + 0.5 at^2

S = 0t + 0.5 X9.8 X t X t

19.6 = 4.9 X t^2

t^2 = 4

Taking Square root on both sides

t = 2 s

v = u + at

v = 0 + 9.8X2

v = 19.6 m

t = 1 ;

v= 9.8 ms-1

t=2 ;

v= 19.6 ms -1

NOW YOU CAN YOURSELF PLOT THE GRAPH

THANK YOU

Answer 2

Answer:

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