Question

An object is dropped from the height of 80m. The Time taken by object to reach the ground is (Take Gravity=10m/s²) Please explain step by step​

Answer 1

Answer:

4 seconds

Explanation:

Given :

• Height from where the object is released = s = 80 metres

• Gravitational force = a = 10 m/s²

• Initial velocity = u = 0 m/s

To find:

• Time taken by the object to reach the ground

Using the second equation of motion :

S=ut+½×at²

80=0×t+½×10×t²

80=5t²

16=t²

t = 4 seconds

The time taken for the object to reach the ground is equal to 4 seconds

Answer 2

Answer :

Given that an object is dropped from the height of 80 m. Gravitational acceleration (g) = 10 m/s²

We have to find time taken by object to reach ground.

From data we have :

Initial speed (u) = 0 m/s. [As the object is dropped freely]

Gravitational acceleration (g) = 10 m/s² [As it drops]

Height (h) = 80 m

We will use 2nd equation of motion to find time taken :

→ h = ut + ½ gt²

Substituting values,

→ 80 = 0 × t + ½ × 10 × t²

→ 80 = 5t²

→ t² = 80/5

→ t² = 16

→ t = √16

→ t = 4 seconds.

Therefore,

∴ Time taken by object to reach ground = 4 seconds.