an object is dropped from the top a multistorey building after two second what will be the magnitude of velocity of an object (g=9.8
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(Final Velocity) = (Initial velocity) + (acceleration)*(time)
therefore,
Final Velocity = (0 m/s) + ( 9.8 m/s² )*(2 sec)
Final Velocity = 19.6 m/s
Velocity after 2 seconds = 19.6 m/s
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Answer:
(Final Velocity) = (Initial velocity) + (acceleration)*(time)
therefore,
Final Velocity = (0 m/s) + ( 9.8 m/s² )*(2 sec)
Final Velocity = 19.6 m/s
Velocity after 2 seconds = 19.6 m/s
Explanation:
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