Question

An object is dropped from the top of a building and strikes the ground 2.0s later. How tall is the building?

Answer 1

Answer:the height of tower is 20 m

Explanation:

u=0 m/s

t=2 s

g=9.8 or 10m/s^2

s=ut+1/2gt^2

s=20 m

Answer 2

the height of the building will be 19.6 meters.

Explanation:

Motion in vertical direction equation is written as,

s = ut - 1/2 gt²

where,

u is initial velocity of the object which is equal to 0

g is the acceleration due to gravity g = 9.8m/s²

therefore the equation becomes,

-h = -1/2 gt²

h = 1/2 * 9.8 * (2)²

h = 19.6 meters

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