Question

An object is dropped from the top of a building and strikes the ground 3.0 s later. How tall is the building?

Answer 1

Answer:

4.41 m

Explanation:

take g=9.80 m/s^2

h= (1/2)gt^2 ,  here v=0

h= (4.9)(9)

h= 44.1 m

Answer 2

Let H be the height of the building,

Initial Velocity (u)= 0 m/s

Therefore, H = ut + 0.5gt²

H = (0)(3) + 0.5(10)(3)² m

H = 0 + 5(9) m

H = 45 m

#Height of building is 45 m