Question

an object is dropped from the top of a building another object is projected with a speed v upward at the same time. magnitude of a relative Accelerationof the object will be
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Answer 1

Answer:

As the second body goes up and comes down and meets the first body, the displacement of the second body is same as that of the first body.

And also when the second body reaches the point of projection, its speed will be same as the speed of projection, let it be u.

For first body, initial speed is zero

Explanation:

V

2

=2gh

For second body,

V

2

−u

2

=−2gh

From these two equations,

2V

2

−u

2

=0

⇒u=2

V

Answer 2

Refer the attachment.....