Question

An object is dropped from the top of a tall building . if the time taken for the object to hit the ground is 8s , calculate the height of the building

Answer 1

Answer:

T=√2h/g

brainliest plz

Answer 2

Answer:

Hey Buddy here's ur answer

Acording to equation of motion

H=ut + 1/2at^2

Here, height=H, u=initial velocity, a=acceleration(acceleratio due to gravity ’g’ in this case),and t is the time taken by object to reach ground.

Here, u=0

t=8s

a=g=9.8m/s^2

Putting all these values in equation

H=0+1/2*9.8*8*8

H=313.6 m

Height of the tower is 313.6 m or 314m