Question

An object is dropped from the top of a tower and it
undergoes free fall. Write the equations of motion for
the object.​

Answer 1

$\it\red{\underline{\underline{Answer:}}}$

$\sf{\underline{Kinematic \ equations:}}$

$\sf{1) \ v=u+at}$

$\sf{2) \ s=ut+\dfrac{1}{2}\times \ at^{2}}$

$\sf{3) \ v^{2}=u^{2}+2as}$

$\sf\blue{Concept:}$

$\sf{For \ body \ in \ a \ free \ fall, \ it's \ initial }$

$\sf{velocity(u) \ is \ zero \ and \ acceleration \ is}$

$\sf{equal \ to \ acceleration \ due \ to \ gravity}$

$\sf{i.e. \ a=g, \ since, \ in \ free \ fall \ the \ body}$

$\sf{moves \ under \ the \ influence \ of \ gravity}$

$\sf{alone.}$

___________________________________

$\sf{\underline{\underline{Equations \ for \ free \ fall}}}$

$\sf{\longmapsto{1) \ v=gt}}$

$\sf{\longmapsto{2) \ s=\dfrac{1}{2}\times \ gt^{2}}}$

$\sf{\longmapsto{3) \ v^{2}=2gs}}$

Answer 2

Answer:

A freely falling body always experience a downward acceleration g which we call as acceleration due to gravity.

Thus acceleration of freely falling body a=g=9.8 m/s

2

(Taking downward direction to be positive)

Initial speed of that body u=0

Equations of motion :

(i) : v=gt

(ii) : S=

2

1

gt

2

(iii) : v

2

=2gS