Question

An object is dropped with no initial velocity above the surface of planet big alpha and falls 13.5 meters in 3 seconds. the radius of planet big alpha is 5.82x10^6

Answer 1

Explanation:

Given An object is dropped with no initial velocity above the surface of planet big alpha and falls 13.5 meters in 3 seconds  the radius of planet big alpha is 5.82 x 10^6 Find the acceleration of falling object and mass of big planet.

• Now we have distance = 13.5 m and time = 3 secs.
• We need to calculate the acceleration. Using equation of motion we get
• S = ut + 1/2 at^2
• Or S = 1/2 at^2
• Or a = 2 x S / t^2
• Or a = 2 x 13.5 / 9
• Or a = 3 m / s^2
• So now we have R as radius, m1 as mass of big planet and m2 as mass of the object.
• So acceleration is due to universal force of gravity.
• So Gm1m2 / R^2 = m2 a
• So m1 = a R^2 / G
•           = 3 x (5.82 x 10^6)^2 / 6.674 x 10^-11
•         = 15.22 x 10^23
•          = 1.522 x 10^24 kg

Reference link will be

https://brainly.in/question/18864791