An object is erect image whose size is double the size of object is placed at a distance of 10cm infront of convex lens.Find power of lens
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Explanation:
Given:u= -10cm
(convex lens)
To find: v and image's nature.
Solution: From lens formula
1 V 1 u 1 f
1 1 + 10 AT = 1 20
1 -1 = V 20
v=-20cm
And magnification = V u
Hence image formed is virtual, erect and magnified two times.
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