An object is falling down from a building .If it takes 3 s to reach ground.the distance b/w building and ground is _______ m ?
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Draw rhombus with one side of length 4.4cm angle of measure 60° Draw its diagonals measue the angles between the diagonals
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Answer:
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Explanation:
Initial Velocity (u) = 0 m/s
Acceleration (a) = 9.8 m/s² [Since acceleration for any object falling down is 9.8 m/s²]
Time (t) = 3 sec
Distance (s) = ?
For finding the distance covered in this case, we'll apply the 2nd Equation of Motion.
2nd Equation of Motion →
We'll substitute the variables from the equation and find the value of 's' now.
∴ The distance between the building and the ground is 44.1 m
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