Question

an object is falling freely under gravity. how distance will travel in 2nd and 3rd second of its journey​

Answer 1

Answer:

Explanation:

It move faster

Answer 2

Answer:

According to equation of motion, distance covered in nth sec.

S

n

=u=

2

a

(2n−1)

S

n

=

2

a

(2n−1)

∴S

1

:S

2

:S

3

={2(1)−1}:{2(2)−1}:{2(3)−1}

=1:3:5