Question

An object is held at 40cm from a concave lens of focal length 60cm. The distance of image from the lens is

Answer 1

Given:

u= -40cm(object distance)

f= -60cm(focal length)

v=?(image distance)

Formula:

$\frac{1}{f} = \frac{1}{v} - \frac{1}{u} \\ - \frac{1}{60} = \frac{1}{v} - ( - \frac{1}{40} ) \\ - \frac{1}{60} = \frac{1}{v} + \frac{1}{40} \\ \frac{1}{v} = - \frac{1}{60} - \frac{1}{40} \\ \\ \frac{1}{v} = - \frac{5}{60} \\ \frac{1}{v} = - \frac{1}{24} \\ v = > - 24cm.$

Hence, the image distance is 24cm.

$itzDopeGirl$

Answer 2

Explanation:

Here is your answer. ..

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