Question

An object is in motion along a straight path along x-axis and its velocity is given by
u= a + Bt
, where a = 2.5 m sh and B = 0.5 m s- and time t is measured in seconds. The object starts
moving from the origin point i.e., at t=0, the object was situated at x = 0.
Now answer the following questions :
(a) Is the object is in a uniform motion ?
(b) What is the acceleration of the moving object ? Is it uniform ?
(c) Draw o-t graph and a-t graph for the given object for a time ranging from t = 0 s to t = 20 s
(d) What is the distance covered by the object in 50 s ?
(2) Calculate the average velocity of the object between t = 10 s and t = 30 s.​

Answer 1

Answer:

a. no

b. acceleration= B=0.5

c. vt graph is a parabola curving upwards, at graph is a straight slope( slanting line)

d. 750m

2. 15m per sec

Explanation:

differentiate eqation with respect to t to get acceleration.

constant acceleration is present equal to b or 0.5

I cant draw graphs here

u have acceleration and initial v so use. s = ut + (a x t x t)/2.

use the same eqn to find distance at time 10 and 30. subtract the two quantitis to get distance covered in the given time, divide this distance with given time period (20 s) and u get avg speed.

PS do the math ur self :) , I hate math