Question

an object is kept a distance of 5 cm infront of a convex mirror of focal length 10 cm . calculate the position and magnification of the image and state it's nature see​

Answer 1

Explanation:

u = -5cm, f = 10cm

We know that

1/v + 1/u = 1/f

⇒ 1/v + 1/-5 = 1/10

⇒ 1/v = 1/10 + 1/5 = 3/10

∴ v = (10/3)cm = 3.33 cm

The position of the image is 3.33 cm behind the convex mirror.

Magnification, m = -v/u = -3.33/-5 = 0.66