An object is kept at 10 cm from a concave lens of focal length 15 cm. Find the distance of the image from the lens and whether the image is virtual or real.
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Answer:
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Explanation:
On measuring distance BC, it will be found to be equal to 6 cm. Thus, the object is placed at a distance of 6 cm × 5 = 30 cm from the lens (as per the original scale). An object 5 cm in length is held 25 cm away from a converging lens of focal length 10 cm.
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