Question

An object is kept at 30cm from a concave mirror of focal length 15cm. Find the image distance and magnification produced by the mirror.

Answer 1

Answer:

$\sf{u=30cm}$

$\sf{f=15cm}$

From mirror formula,

$\sf{{\dfrac{1}{f}}={\dfrac{1}{v}}+{\dfrac{1}{u}}}$

$\sf{-{\dfrac{1}{15}}+{\dfrac{1}{30}}=1}{v}}}$

$\sf{{\dfrac{1}{v}}={\dfrac{-2+1}{30}}}$

$\sf{{\dfrac{1}{v}}=-{\dfrac{1}{30}}}$

$\sf{v=-30cm}$

Answer 2

Explanation:

ans is mentioned in pic

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