Question

an object is kept at a distance of 10cm from the focus of the mirror.
which forms its erect image as half the size of object.
find f, u, v

please answer this question i will the branliest​

Answer 1

Answer:

Since the image is erect , so the magnification ratio must be positive .

m=2

also u=−10cm

$m = \frac{v}{u}$

$2 = \frac{v}{ - 10}$

v=20cm

So the image is virtual and 20 cm from mirror on the other side of the object.