Question

An object is kept at a distance of 15 cm from a convex lens of focal length 10
cm. Calculate the image distance and state the characteristics of the image
formed
.

Answer 1

U =-15

F =10

V =?

So by lens formula

We get.....

Answer 2

Answer: The image is formed at 30 cm on the other side of the lens and image is inverted and real.

Explanation:

Given that,

Distance of the object u = -15 cm

Focal length f = 10 cm

Using the lens formula

$\dfrac{1}{f}=\dfrac{1}{v}-\dfrac{1}{u}$

$\dfrac{1}{10}+\dfrac{1}{-15}=\dfrac{1}{v}$

$\dfrac{1}{v}= \dfrac{1}{30}$

$v = 30 cm$

The distance of the image is 30 cm.

The magnification is

$m = \dfrac{v}{u}$

$m = \dfrac{30}{-15}$

$m = -2$

Negative sign represent the image is inverted and real.

Hence, The image is formed at 30 cm on the other side of the lens and image is inverted and real.