An object is kept at a distance of 30 cm from a diverging lens of focal
length 15 cm. At what distance the image is formed from the lens? Find the
magnification of the image.
Answers
Step-by-step explanation:
Substitute f=−30cm and v=−15cm to find the value of u. Substitute, v=−15cm, u=−30cm and h1=5cm to find the value of h2. Therefore, the object should be placed 30 cm from the optical centre and the size of the image formed is 2.5 cm.
Plese make me brainliskt
Answer:
ok let me help u
Step-by-step explanation:
Distance to the left focal point (which is right of the lens for a negative lens) is 45cm. In focal lengths that is 3 focal lengths. Meaning that the magnification will be 1/3 and the image will be 1/3 focal lengths = 5cm from the right focal point (which is to the left of the lens for a diverging one). That is 10 cm from the lens on its left side
Exact and general formulas:
Defining the focal points through focal length and lens:
FL = L-F,Fr = L+F
Object gives the magnification: 1/M = obj-fl/ f
Magnification gives the image: M= img-fr/f
img= fr+ f x m
hope it helps
over nd happy to help
diagram below for refrence
