Question

an object is kept at a distance of 5 cm from convex lenses of focal length 15 CM identify the position and nature of the image​

Answer 1

Answer:

Position : on the smae side of the object

Nature : magnified, virtual and erect

Answer 2

Answer:

u,f is +ve for convex lens and since object is kept between focal point and lens nature is virtual and upright and magnified,therefore v is -ve.

$1/v-1/u=1/f$

$-1/v=1/f-1/u\\-1/v=-2/15\\v=7.5$

Explanation:

v is image dist,f is focal length and u is object distance.