Question

an object is kept at a distance of 5 cm in front of a convex mirror of focal length 10 cm . calculate the position and magnification of the image ​

Answer 1

Hey mate,

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object distance: U = – 5cm

focal length: f = 10cm

image distance: V = ?

formula used :

lens formula: 1/f = 1/v – 1/u

magnification: m = h2 / h1 => v/u

So,

1 / 10 = 1 / v – 1 / -5

here for v.

1 / v = 1 / 10 + 1 / 5

on solving,

1 + 2 / 10 = 1/v

3 / 10 = 1/v

V = 10 / 3

V = 3.33cm.

Magnificent:

m = v/u

so,

m = 10/3 × 1/5

on solving we get,

m = 0.666cm.

position image: behind the mirror.

nature of image: virtual & erect.

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Hope it helps you...!!!

All the best for exams....✌✌

Answer 2

Answer:

Hi,

begin mathsize 12px style Given space straight u space equals space minus 5 space cm space and space straight f space equals space 10 space cm

Using space the space mirror space formula space 1 over straight v equals 1 over straight f minus 1 over straight u

1 over straight v equals 1 over 10 minus fraction numerator 1 over denominator left parenthesis negative 5 right parenthesis end fraction equals 3 over 10

straight v space equals space 3.33 space cm

Thus comma space image space formed space is space virtual space in space nature.

end style