Question

An object is kept at a distance of 5cm in front of a canvex mirror of a focal lenth 10cm. Calculate the position and magnification of the image and state its nature.​

Answer 1

Hello my dear friend I am here to help you

Answer 2

Answer

from the formula of convex mirror..

$= > \frac{1}{v} + \frac{1}{u} = \frac{1}{f}$

here...u=-5cm,f=10cm

therefore...

$\frac{1}{v} + \frac{1}{ - 5} = \frac{1}{10} \\ = > \frac{1}{v} = \frac{1}{10} + \frac{1}{5} \\ = > \frac{1}{v} = \frac{3}{10} \\ = > v = \frac{10}{3}$

therefore.

$m = - \frac{v}{u} = - \frac{ \frac{10}{3} }{ - 5} = \frac{10}{15} \\ = > m = \frac{2}{3}$

......