Question

An object is kept at a distance of 5m in front of a spherical mirror, which forms its erect image at a distance of 2m from the mirror. What is the magnification? Is the mirror concave or convex?

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Answer 1

Given:-

• Object distance,u = 5m
• image distance ,v = 2m
• Image formed is erect .

To Find:-

• Magnification ,m

Solution:-

According to the Question

The mirror formed erect image . It means that image formed is virtual . Using magnification formula

• m = -v/u

where

• m denote magnification
• v denote image distance
• u denote object distance

Substitute the value we get

$:\implies$ m = -2/-5

$:\implies$ m = 2/5

$:\implies$ m = +0.4

• Hence, the magnification of the mirror is 0.4 .

here, the magnification is positive . So the mirror is convex .

Answer 2

Answer:

Given :-

• An object is kept at a distance of 5 m in front of a spherical mirror, which is erect image at a distance of 2 m from the mirror.

To Find :-

• What is the magnification.
• What type of mirror it is.

Formula Used :-

$\clubsuit$ Magnification Formula :

$\longmapsto \sf\boxed{\bold{\pink{ Magnification\: (m) =\: \dfrac{- v}{u}}}}$

where,

• v = Image Distance
• u = Object Distance

Solution :-

Given :-

$\bigstar$ Object Distance (u) = - 5 m

$\bigstar$ Image Distance (v) = 2 m

According to the question by using the formula we get,

$\longrightarrow \sf Magnification\: (m) =\: \dfrac{- 2}{- 5}$

$\longrightarrow \sf Magnification\: (m) =\: \dfrac{\cancel{-} 2}{\cancel{-} 5}$

$\longrightarrow \sf Magnification\: (m) =\: \dfrac{2}{5}$

$\longrightarrow \sf\bold{\red{Magnification\: (m) =\: +\: 0.4}}$

$\therefore$ The magnification is + 0.4.

Now, we have to find which type of mirror it is :-

As we can notice that :-

• The magnification has positive sign (+ve).
• The image is erect and diminished.

$\therefore$ The mirror is convex mirror.