Chemistry, asked by XxJeenRoyxX, 1 month ago

An object is kept at a distance of 5m in front of a spherical mirror, which forms its erect image at a distance of 2m from the mirror. What is the magnification? Is the mirror concave or convex?​

Answers

Answered by nishantmohapatra1308
1

Answer:

Given:-

Object distance,u = 5m

image distance ,v = 2m

Image formed is erect .

To Find:-

Magnification ,m

Solution:-

According to the Question

The mirror formed erect image . It means that image formed is virtual . Using magnification formula

m = -v/u

where

m denote magnification

v denote image distance

u denote object distance

Substitute the value we get

m = -2/-5

m = 2/5

m = +0.4

Hence, the magnification of the mirror is 0.4 .

here, the magnification is positive . So the mirror is convex .

If this helps you a brainliest would be awesome.

Answered by Liam450
3

■ Given that:-

▪︎An object is kept at a distance of 5m in front of a spherical mirror, which forms its erect image at a distance of 2m from the mirror.

▪︎Object Distance(u)= 5cm , Image Distance(v)=2 m , Image Formed is Erect.

■ To Find :-

Magnification of the mirror(m)Mirror is Concave or Convex.

■ Solution:-

▪︎According to the Question

▪︎Image Formed if Erect.

▪︎Which means the image is Virtual

▪︎Then we use Magnification Formula

m = \frac{ - v}{u}

So, we will Substitute the Value in this equation

m = \frac{ - 2}{ - 5}

m = \frac{2}{5}

m = 4

The magnification of the mirror is 4cm

Which is Positive

So, The Mirror is Convex.

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