An object is kept at a distance of 5m in front of a spherical mirror, which forms its erect image at a distance of 2m from the mirror. What is the magnification? Is the mirror concave or convex?
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Answer:
Given:-
Object distance,u = 5m
image distance ,v = 2m
Image formed is erect .
To Find:-
Magnification ,m
Solution:-
According to the Question
The mirror formed erect image . It means that image formed is virtual . Using magnification formula
m = -v/u
where
m denote magnification
v denote image distance
u denote object distance
Substitute the value we get
m = -2/-5
m = 2/5
m = +0.4
Hence, the magnification of the mirror is 0.4 .
here, the magnification is positive . So the mirror is convex .
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Answered by
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■ Given that:-
▪︎An object is kept at a distance of 5m in front of a spherical mirror, which forms its erect image at a distance of 2m from the mirror.
▪︎Object Distance(u)= 5cm , Image Distance(v)=2 m , Image Formed is Erect.
■ To Find :-
Magnification of the mirror(m)Mirror is Concave or Convex.
■ Solution:-
▪︎According to the Question
▪︎Image Formed if Erect.
▪︎Which means the image is Virtual
▪︎Then we use Magnification Formula
So, we will Substitute the Value in this equation
∴The magnification of the mirror is 4cm
Which is Positive
So, The Mirror is Convex.
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