Question

An object is kept at a distance of 5m in front of a spherical mirror, which forms its erect image at a distance of 2m from the mirror. What is the magnification? Is the mirror concave or convex?

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Answer 1

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u = +5cm, f = 2cm

We know that

1/v + 1/u = 1/f

⇒ 1/v + 1/-5 = 1/10

⇒ 1/v = 1/10 + 1/5 = 3/10

∴ v = (10/3)cm = 3.33 cm

The position of the image is 3.33 cm behind the convex mirror.

Magnification, m = -v/u = -3.33/-5 = 0.66

The image is virtual and erect.

Answer 2

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* Solutions *

U = 4m

V = 1m

By sing Conversation , U = 4m

: M = 1/4

= 0.2

As the mangnifition is positive and Diminished hence the mirror could be convex ...