Question

an object is kept at a height of 300 M is allowed to fall due to the effect of gravity then calculate the time taken by the object to reach the ground

Answer 1

Height =distance covered =300 m=S.
$s = ut + \frac{1}{2}a {t}^{2}$
a=10 ms^-2. initially the object is at rest so u=0.
300=0(t)+1/2(10)t^2
=> 300=5t^2
=> 60=t^2
=> 2√15=t
=> t=2(3.873)
=> t=7.746 seconds is the time taken by the object to the ground.