Question

an object is kept in front of a concave mirror of focal length 20 cm. the image is three times the size of object. calculate two possible distances of object from mirror ?

Answer 1

Hey guys this is Nitish singh

Given , f= -20
m = +3 or -3 (two different positions)

m = -v/u
3= -v/u
v = -3u. [1]

1/f=1/v+1/u
thus, 1/-20 = 1/-3u + 1/u. ( from 1 replacing v)
1/-20 = 2/3u
​3u = -40.  (Cross multiplying)
u= -40/3


Now if m = -3
m = -v/u
-3 = -v/u
v= 3u. [2]

1/f= 1/v + 1/u
1/-20= 1/3u + 1/u.  (Replacing v by [2])
1/-20=4/3u
3u = -80
u= -80/3 cm

Thus the two positions are -40/3 cm and -80/3 cm

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