an object is kept in front of a concave mirror of focal length 30 cm the image formed is 3 times the size of the object find the distance from the mirror at which a screen should be placed in order to obtain a sharp image also find the size and nature of the image formed
pls correct answer with explanation
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Answer:
Given: u=−20 cm
f=R/2=15 cm
Size of image, h=5 cm
Let size of image be h
′
From mirror formula,
u
1
+
v
1
=
f
1
−20
1
+
v
1
=
15
1
v=
7
60
=8.57 cm
The image is formed 8.57cm behind the mirror. It is virtual and erect.
Magnification, m=−v/u=8.57/20=0.428
Also, m=h
′
/h=h
′
/5
From above, h
′
/5=0.428
h
′
=2.14 cm
Explanation:
simalar do with this method
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