an object is kept in front of concave mirror of focal length 15cm .the image formed is 3 times a size of the object .calculate the position of the object from the mirror..
pls help!!!
Answers
Answered by
88
f= -15cm
m= -3 or+3
case 1
m= -v/u
-3=-v/u
v= 3u----------[1]
1/f=1/v+1/u
1/-15=1/3u+1/u ---------from eqn. [1]
1/-15=4/3u
3u=-60
u=-60/3cm
CASE 2
3=-v/u
v=-3u------[2]
1/f=1/v+1/u
1/-15=-1/3u+1/u
-1/15=2/3u
-3u=30
u=-10
m= -3 or+3
case 1
m= -v/u
-3=-v/u
v= 3u----------[1]
1/f=1/v+1/u
1/-15=1/3u+1/u ---------from eqn. [1]
1/-15=4/3u
3u=-60
u=-60/3cm
CASE 2
3=-v/u
v=-3u------[2]
1/f=1/v+1/u
1/-15=-1/3u+1/u
-1/15=2/3u
-3u=30
u=-10
Similar questions