An object is kept on the principal axis of a concave mirror of focal length
12 cm. If the object is at a distance of 18 cm from the mirror, calculate the
image distance. Determine the nature of the image formed by calculating
the magnification produced by the mirror.
Answers
Answer:The sign conventions for the given quantities in the mirror equation and magnification equations are as follows: f is + if the mirror is a concave mirror f is - if the mirror is a convex mirror d i is + if the image is a real image and located on the object's side of the mirror.
Explanation:
Answer:
Hence, the position of the image is - 36 cm.
Nature : The image is Real and Inverted and enlarged.
Magnification, m = - 2
Explanation:
Given,
Mirror = Converging, Concave mirror
Position of object, u = - 18 cm
Focal length of the mirror, f = - 12 cm
Let the position of image be 'v'.
Then, by mirror formula, we know that,
1 / f = 1 / v + 1 / u
=> 1 / v = 1 / f - 1 / u
=> 1 / v = (-1) / 12 - (-1) / 18
=> 1 / v = (-3) / 36 + 2 / (36)
=> 1 / v = - 1 / 36
=> v = - 36 cm
Hence, the position of the image is - 36 cm.
Nature : The image is Real and Inverted and enlarged.
Since the image is formed on the same side of mirror, it is real and inverted.
We know that,
Magnification, m = - v / u
=> m = - (-36) / (-18) = - 2
Hence, the magnification of the image is - 2