Question

An object is kept on the principal axis of a concave mirror of focal length

12 cm. If the object is at a distance of 18 cm from the mirror, calculate the
image distance. Determine the nature of the image formed by calculating
the magnification produced by the mirror.​

Answer 1

Answer :

Given -

• Concave mirror
• Focal length = - 12 cm
• Object Distance = - 18 cm

To Find -

Mirror Formula : 1/v + 1/u = 1/f.

⇒ 1/v + 1/-18 = 1/-12

⇒ 1/v = -1/12 + 1/18

⇒ 1/v = (-18 + 12)/216

⇒ 1/v = -6/216

⇒ 1/v = - 0.02

⇒ v = 1/- 0.02

⇒ v = - 50 cm

Hence, Image Distance = - 50 cm.

• The Nature of the Image will be : Real and Inverted.
• The Size of the Image will be : Enlarged.
• The Position of the Image will be : Beyond C.

Magnification = -v/u

⇒ -(-50)/-18

⇒ -50/18

⇒ -2.7

So, the Magnification of the Image is -2.7.

Answer 2

Answer:

Explanation:this may help you

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