Question

An object is launched at a velocity of 20 m/s in a direction making an angle of 25° upward with the
horizontal.
a) What is the maximum height reached by the object?

Answer 1

Answer:

Answer. In the problem V0 = 20 m/s, θ = 25° and g = 9.8 m/s2. The height of the projectile is given by the component y, and it reaches its maximum value when the component Vy is equal to zero. That is when the projectile changes from moving upward to moving downward.