Question

An object is launched into the air. The projectile motion of the object can be modeled using the function
h(t) = –16t2 + 72t + 5, where t is the time in seconds since the launch and h(t) represents the height in feet of the object after t seconds. What is true about the projectile motion of this object? Check all that apply.

The initial height is 5 feet.

The initial velocity of the object is –72 feet/second.

The object will hit the ground after approximately 4.57 seconds.

After 3 seconds, the object is 173 feet high.

At t = 0, h(t) = 0.

Answer 1

Answer:

An object is launched into the air. The projectile motion of the object can be modeled using the function h(t) = –16t2 + 72t + 5, where t is the time in seconds since the launch and h(t) represents the height in feet of the object after t seconds. [ The following are true about the projectile motion of this object: The initial height is 5 feet and The object will hit the ground after approximately 4.57 seconds. Solution: a=-16, b= 72, c= 5; t= -0.06 and t= 4.568; h(t) = -16(3)^2 + 72(3) + 5=77; At t=0 , h(0) = 5. ]

Answer 2

Answer:

a-c

Step-by-step explanation:

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