Question

an object is let to freely falling under gravity if it reaches the ground in 5 second then calculate its velocity ¡) just before reaching the ground and the distance travelled by an object in the given time .« take Gravitation equals to 10 metre per second square».​

Answer 1

Given, a = 10 m/s^2; t = 5 s; u = 0

Then velocity just before reaching the ground (v) = u + at = 50 m/s

And, the distance covered (s) = (v^2 - u^2)/2a = (2500 /20) m = 125 m

HOPE THIS COULD HELP !!!