An object is moving in a straight line with constant velocity has kinetic energy E and mimentum P . if the speed of the object is doubled the new value of its momentum and kinetic energy becom
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let initial speed be v
then
E=1/2mv²
P=mv
new speed be v'
v'=2v
E'=1/2mv'²
=1/2m(2v)²
=1/2m*4v
=4E
P'=mv'
=m*2v
=2P
new kinetic energy is 4 times the original and new momentum is twice the original
hope this helps
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FOR AN OBJECT
K.E.=1/2mv^2
K.E. directly proportional to v^2
so if velocity is doubled
K.E. becomes 2^2 i.e. 4 times .
Assuming P to be linear momentum
P=mv
P directly proportional to v^1
if velocity is doubled momentum is 2^1 times i.e. 2 times
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