Question

An object is moving with a uniform velocity along a particular direction. A retarding

force of 5N, is applied in the direction as shown. The object stops after a displacement of

5m. What is the work done by the retarding force?​

Answer 1

Answer:

The work done is negative.(-25N)

Explanation:

W= WORK DONE

F=FORCE ACTING ON THE OBJECT

S=DISTANCE/DISPLACEMENT/HEIGHT

W = F*S (For positive work) Eq. 1

W = -F*S (For negative work) Eq. 2

HERE, we will use Eq. 2

Substituting all the values, we get

W =-F*S

W = -5*5

W = -25 N

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