Question

AN OBJECT IS MOVING WITH A VELOCITY OF 20 M PER SECOND COME TO REST IN 5 SECOND FIND ACCELERATION AND DISTANCE OF THE OBJECT

Answer 1

Answer:Initial velocity (u)=20m/sec

Final velocity(v) =0 m/sec

Time (t)=5 s

Therefore , acceleration(a) =(v-u)/t=(0-20)/5=-20/5=-4m/sec^2

Distance (S)=ut+1/2at^2=20*5+1/2*-4*5^2=100+(--10)=100-10=90 m.

Explanation:Hope it helps.