Question

An object is moving with an acceleration of 12m/s2.Find the distance covered by it after 3 seconds, if its initial velocity is 5m/s​

Answer 1

Answer:

a= 12 m/s²

t= 3 sec

u = 5 m/s

therefore, v =

a = (v-u)/t

12 = (v-5)/3

12x3 = v-5

36+5= v

41 m/s = v

therefore the object will cover 41 m.

Explanation:

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