Question

An object is moving with initial velocity 10 m/s with a constant acceleration of -2 m/s². The total distance travelled by the object in 6 sec​

Answer 1

Answer:

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Answer 2

Explanation:

we know, equation for distance S travelled by obj. moving with acceleration a is given by,

S = ut+ 1/2 at^2

Here, u= 10m/s , a=-2 m/s^2, t=6s

therefore, S = 10×6 + 1/2× (-2) ×6^2

=60-36

= 24m