Question

an object is moving with initial velocity of 25ms-1 and after 10s it reaches a final velocity of 50ms-1.find its acceleration​

Answer 1

Given :-

• Initial velocity (u) = 25m/s
• Final velocity (v) = 50 m/s
• Time taken = 10 seconds

To Find :-

Acceleration of the object

$\sf \orange{Formula \: used : - }$

${\boxed {\sf\longrightarrow \pink {a = \frac{v - u}{t} }}}$

Where,

• a = acceleration
• v = final velocity
• u = initial velocity
• t = time taken

Substituting the values, we get

$: \implies \sf \frac{50m/s - 25m/s}{10s} \: \: \: \: \: \: \\ : \implies \sf \frac{ 25m/s}{ {10}s} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ : \implies \sf \: \frac{ \cancel{25}m/s}{ \cancel{10s}} = 2.5m/ {s}^{2}$

$\sf \therefore \purple{Acceleration \: of \: the \: object = 2.5m/s²}$

Answer 2

The reaches a final to its acceleration $2.5ms^{-2}$.

Explanation:

Acceleration $a=\frac{v-u}{t}$

$=\frac{50ms^{-1}-25ms^{-1}}{10s}$

$=\frac{25ms^{-1}}{10s}$

$=2.5ms^{-2}$.