Question

An object is moving with uniform speed in a circular path of radius 70m calculate the distance &displacment -when it complete half a circle

Answer 1

Distance travelled by object = half the circumference

→ 1/2 × 2πr

→ πr

Taking π as 22/7,

22/7 × 70

→ 220 metres.

Hence, distance travelled = 220 metres.

After completing half a circle, the object will be diametrically opposite to it's inital position. Now we know that displacement is the shortest distance between initial and final position. Hence, it's displacement will equal the value of diameter of the circle.

Diameter of circle = 2 × R = 2 × 70 m = 140 m

Hence, magnitude of displacement = 140 m

Answer 2

⚜️ GIVEN ⚜️

An object is moving with uniform speed in a circular path of radius 70 m.

⚜️ TO FIND ⚜️

The distance and the displacement of the object.

⚜️ SOLUTION ⚜️

We know, distance is the total length of the path covered between the initial position and the final position.

displacement is the shortest length of the path between the initial position and the final position.

For distance :-

s = 1/2 × Perimeter of the circular path

⇒s = 1/2 × 2πr

⇒s = 22/7 × 70

⇒s = 220 m

$\rule{150}3$

For displacement :-

s = Diameter of the circle (for completing half a round)

⇒s = 2r

⇒s = 2 × 70

⇒s = 140 m

Therefore, the object covers a distance of 220 m and has an overall displacement of 140 m.