Question

An object is moving with uniform velocity of 6 m/s. The
acceleration of the object after 4 sec will be in
(in m/s2)
1. 1.5
2.0.666
3.0
4. 24​

Answer 1

Answer:

A body moving with a velocity of 6 m/s uniformly accelerates at 1.5 m/s2 .what will be its velocity after 5 seconds and how far will it move during this time?

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We will start with calculating the final velocity:

Vf = Vi + a*t

Vf= Final Velocity (m/s)

Vi = Initial Velocity (m/s)

a = Acceleration (m/s^2)

t = Time (seconds)

We will plug in the appropriate information into the formula:

Vf = (6 m/s) + ((1.5 m/s^2)*(5 seconds))

Vf= (6 m/s) + (7.5)

Vf= (13.5 m/s)

We will calculate the distance covered:

D= (Vi)*(t) + (1/2)*(a)*(t^2)

D= distance (meters)

vi= initial velocity (m/s)

t=time (seconds)

a= acceleration (m/s/s or m/s^2)

D = (6 m/s)*(5 sec) + (1/2)*(1.5 m/s^2)*(5^2)

D= (30)+ (18.75)

D= (48.75 meters)

I hope this helps ! All the best !

Answer 2

ANSWER:

The answer is option 4. 24m/s^2