Question

An object is moving withvelocity 20 m per second is retarded by an acceleration -2m per second² find distance and displacement of object after 12 sec​

Answer 1

Explanation:

initial velocity (u) = 20m/s

Time taken (t) =12 s

acceleration (a) = -2m/s²

therefore, distance = ut +1/2 . a. t²

= {(20×12) + 1/2 × 2 × (12)²}m

= {240+144}m

=384 m