Question

An object is observed to move such that its velocity changes from 1 m/s to 7 m/s in 3 seconds.
Calculate the acceleration of the object and its displacement in 3 seconds.

Answer 1

Answer:

acceleration = 2 [ m/ (s^2) ]

Displacement = 12 m

Explanation:

Acceleration = change in velocity /change in time

= (7-1) / (3-0)

= 6/2

= 2 [ m / (s^2)]

Displacement

S = ut + (1/2)at*t

OR use v*v = u*u + 2as

Value of S = 12 m