an object is of size 7.0cm is placed at 27cm in front of a concave mirror of focal length 18cm . At what distance from the mirror, should the screen be placed, so that a sharp image can be obtained? Find the size and nature of the image?
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Explanation:
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Given:
size of object, o=+7cm
distance of object ,u=−27cm
focal length of concave mirror, f=−18cm
let us take size of image=I
so, mirror formula is
v1+u1=f1
so, putting values of u and v,
v1=−181−−271
v1=−541
v=−54cm
so, image is formed on object side only.
magnification,
m=u−v=oI
m=−−27−54=7I
I=−14cm
so, image is double in size to that of object.
Nature: real, inverted and magnified image.
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