An object is oscillating about certain mean position.Its time period of oscillation is being measured bya stop watch of least count 0.1 s. For 20 oscillations the time noted down is 40.0 s. Thenfractional error in measurement of time period of oscillation is -a) 1/20b) 1/400c) 1/200d) 1/40
Answers
fractional error=least count÷measured value
0.1÷.40=.0025=1/400
The fractional error in the measurement of the time period of oscillation is 1/400.
Given,
Least count = 0.1s
The time measured for 20 oscillations = 40.0s
To Find,
The Fractional error.
Solution,
Before solving the question, let's understand the concept and formula for fractional error.
A measure of the mean absolute error in relation to a mean value (or a relative error in relation to that value) or fractional error in relation to that value.
Formula:-
Fractional error = least count / measured value.
Now, let's solve the question using the above formula.
Fractional error = least count / measured value.
Fractional error = 0.1s / 40.0s
On dividing, we get,
Fractional error = 0.0025 or 1/400.
The fractional error in the measurement of the time period of oscillation is 1/400.
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