Question

An object is placed 10 cm from aconcave mirror. The focal length is 5 cm. Determine (a) The image distance (b) the magnification of image​

Answer 1

Given:

u= -10cm

f= -5cm

v=?

m=?

(a)

1/f = 1/v-1/u

1/-5 = 1/v-(1/-10)

1/-5 = 1/v + 1/10

1/-5 - 1/10 = 1/v

1/-5*2/2 - 1/10 = 1/v

-2/10-1/10 = 1/ v

-3/10 = 1/v

v = 10/-3

v = -3.33cm

(b)

m = v/u

m = -3.33/-10

m = 3.33/10

m = 0.33